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Am I insane?

Yes
47
77%
No
14
23%
#184063
If anyone was wondering whether Superman is capable of sucking water through a 50 meter straw, the answer is no, apparently he is not. He does make a great barometer though.
#184066
Regarding the poll, I now realize (as I did not when I wrote the poll question), that the word "insane" has the capability to be offensive and damaging to those who are mentally ill. I was ignorant when I wrote it, but that is no excuse. For this, I would like to apologize.

~dlgn
#184069
Great. Just great deel. I was just about to make a humerus comment about Superman and you just wreck the possability with... SERIOUSNESS.
Honestly, I must ask,
Where in this thread does seriousness belong? Because I'm pretty sure it doesn't.
So... TL;DR:
Bet said by someone who IS "insane"...
Image
#184072
Where in this thread does seriousness belong?
Where it is needed. It was needed there. Now it isn't anymore for the moment, as evidenced by your post.
#184136
Out of curiosity, I decided to see what the rates of change of a few different types of energy are with respect to a few different quantities, and my head exploded. (K is kinetic energy, u is potential energy, and G is Gibbs free energy.)

dK/dv=mv=p (momentum)
dK/dt=mv*dv/dt=mva=p*a=v*F= P (power)
dK/dx=????? (Possibly force?)
du(g)/dh=mg=Force of gravity on earth
du(s)/dx=-kΔx=Force of a perfect spring
dG/d(pressure)=Volume
dG/d(volume)=Pressure
dG/dx=mΔvcosθ (I think?)
dG/dF=Δxcosθ (??)
dG/dN=(K_b)T

???

!!!

:?: :!:

CUBE HELP ME
#184162
dlgn wrote: dK/dx=????? (Possibly force?)
Kinetic energy is just the integral of momentum with respect to velocity. Think of it this way: an object only gains kinetic energy by having work done on it (force exerted on it) over a distance.

KE = ∫ F dx
F = ma = m dv/dt
= ∫ m dv/dt dx
(using chain rule) = ∫ mv dv/dx dx
= 0.5 mv^2

Does this help?

I don't know about the others since I never learned about Gibbs free energy in enough detail. :P
#184167
Eetrab wrote:
dlgn wrote: dK/dx=????? (Possibly force?)
Kinetic energy is just the integral of momentum with respect to velocity. Think of it this way: an object only gains kinetic energy by having work done on it (force exerted on it) over a distance.

KE = ∫ F dx
F = ma = m dv/dt
= ∫ m dv/dt dx
(using chain rule) = ∫ mv dv/dx dx
= 0.5 mv^2

Does this help?

I don't know about the others since I never learned about Gibbs free energy in enough detail. :P
That makes sense, thanks Eetrab.

And I believe Gibbs free energy is basically "work potential". Not exclusively potential energy but any energy that has the capability to be transferred as work. It's equal to PV and also (through the ideal gas law) nRT. The rest of the energy is "enthalpy" which is energy that has the capability to be transferred in the form of heat. I'm not entirely sure how chemistry!Thermodynamics and physics!Thermodynamics are related, though, and the relationship between Gibbs free energy and enthalpy (mainly chemistry concepts) and work and heat (primarily in physics) is one of the big things that's quite confusing to me. Basically, though,

W=ΔG and Q=ΔH

and that's reasonably comprehensible.

~dlgn
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