Re: Skulleh's Miscellaneous Thread
Posted: Fri May 16, 2014 12:16 pm
Enjoy.
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Skulleh's Miscellaneous Thread
https://www.minerealm.com/community/viewtopic.php?f=26&t=15132
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Re: Skulleh's Miscellaneous Thread
Posted: Mon May 19, 2014 8:54 am
So yeah.... stoof
Re: Skulleh's Miscellaneous Thread
Posted: Tue May 20, 2014 2:21 pm
oh god
Re: Skulleh's Miscellaneous Thread
Posted: Wed May 21, 2014 12:33 am
dlgn wrote:oh god?
R(CD) = R(EF) = 6ohms
R(AB) = 3 ohms
Re: Skulleh's Miscellaneous Thread
Posted: Wed May 21, 2014 4:27 am
TeeJayDub wrote:R(AB) is true, yet what I see is:dlgn wrote:oh god?
R(CD) = R(EF) = 6ohms
R(AB) = 3 ohms
C and E are connected.
D and F are connected.
Resulting in R(CD) = R(EF) = R(AB) = 3 ohms.
tl;dr: Resistance is futile!
Re: Skulleh's Miscellaneous Thread
Posted: Wed May 21, 2014 6:04 am
Redkiller123 wrote:Resulting in R(CD) = R(EF) = R(AB) = 3 ohms.Absolutely, when considering the full circuit. I meant the resistance of that half of the circuit in isolation, showing how I'd arrived at the R(AB) solution. I should have explained that though because yes, what I've written is technically rather incorrect
tl;dr: Resistance is futile!
Re: Skulleh's Miscellaneous Thread
Posted: Sun May 25, 2014 3:57 pm
Super heroes stoof
Re: Skulleh's Miscellaneous Thread
Posted: Sun May 25, 2014 7:40 pm
Just because.
Re: Skulleh's Miscellaneous Thread
Posted: Mon May 26, 2014 10:34 pm
Na na na na na na BATMAN!!!
Re: Skulleh's Miscellaneous Thread
Posted: Wed May 28, 2014 1:31 pm
I miss you Skull!!!! <3